Integer input of ShaderFX does not update

[bjoern]

Shader looks like this:

shader Invert_Advanced_Internal_ShaderFX : ComputeFloat4, InvertOperations
{
    [Default(0.0, 0.0, 0.0, 1.0)]
    compose ComputeFloat4 ColorIn;

    [Default(1.0)]
    compose ComputeFloat Factor;

    bool InvertAlpha = false;
    int InvertType;

    override float4 Compute()
    {
        return Invert(ColorIn.Compute(), Factor.Compute(), InvertAlpha, InvertType);
    }
};

When I change InvertType in the patch it does not update in the shader, no matter if I use an enum, Enum2Ord or an integer directly.

It works though if the int is changed inside the code, for example by setting a default, like so:

int InvertType = 2;

Same thing as TextureFX works without problems.

shader Invert_Internal_TextureFX : FilterBase, InvertOperations
{
    [Default(1.0)]
    compose ComputeFloat Factor;

    bool InvertAlpha = false;
    int InvertType;

    float4 Filter(float4 tex0col)
    {
        return Invert(tex0col, Factor.Compute(), InvertAlpha, InvertType);
    }
};

SFX-Int.7z (33.3 KB)

[tonfilm]

Do other types work, like float and bool? Or is this a general thing for uniform inputs?

Made an issue for it:
https://github.com/vvvv/VL.StandardLibs/issues/647

[bjoern]

Also happens with float and bool.

SFX-Float-Bool.7z (3.0 KB)

[tonfilm]

It works if you add the stage keyword, but then you can only have one instance of a node per shader graph. because stage makes sure there is only one variable of that name per compiled shader.

[tonfilm]

The original ShaderFX Lerp doesn’t have this issue, so it is definitely some bug with the shader key management.

[bjoern]

@tonfilm

you can only have one instance of a node per shader graph.

What counts as one graph in this context?

Like so, And B wouldn’t work when Switch uses the stage keyword?

[tonfilm]

Yes, a graph is all nodes that are part of one final shader. B would be compiled, but the Condition input would only exist once in the shader and therefore the last change would set both switches.