I’been trying a lot entering diferent values in the x y z fields, trying with spreads and I can’t get to draw to the triangle I want. Even with checking the F1’s node. Some can get a little light on me?
can you upload a simple patch that you tried and does not work for you? then we can probably give you a better hint…
like that, I only get that triangle with that spread count, otherwise it renders a line at diferent length. And without the linearspread it renders nothing
ok, so:
the Triangle node most importantly takes Vertices (ie. corner-points for the triangles) via pins: X, Z, Z and Indices via pins: Index 1, Index 2, Index 3.
you can feed it a spread of vertices in any order and then use always 3 indices to select 3 corner-points from the pool of vertices to draw one triangle.
the Index pins are initialized to 0, 1 and 2 and will thus select the first, second and third vertex in the spread to draw a triangle.
in your example you use a LinearSpread which creates linearly distributed values and use always three consecutive of those values as a vertex for your triangles. the resulting triangle is rather unpredictable…
for 3 vertices you need 9 (= 3 * XYZ) values. it is in the nature of the Vector (Split) that if you feed it 6 values it will return 2 split vertices, as 6 values make 2 vertices. if you feed it 7 values it will already return 3 split vertices even though it is actually missing 2 more values. instead of complaining it simply takes the first two (of the seven) values again…
i suggest you replace the LinearSpread with a RandomSpread for a more meaningful test…
if you want to draw more than one triangle you need to specify more indices. to select more of the vertices you provide…
